Deriving Rate Laws

Rate of rxn = k [CH3CHO]2

Here the rate goes up by FOUR when initial conc. doubles. Therefore, we say this reaction is Second order.

Now determine the value of k. Use expt. #3 data—

0.182 mol/L•s = - k (0.30 mol/L)2

k = - 2.0 (L / mol•s)

Using k you can calc. rate at other values of [CH3CHO] at same T.

Not

Given

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